Question
Question: How do you evaluate \({\log _6}2\) ?...
How do you evaluate log62 ?
Solution
In this question we have to use the identities of logarithm. Like first we need to convert its base into exponential using the formula logba=logeblogea. Then we have to put the values of different logarithmic numbers.
Complete step by step answer:
In the above question it is given that log62. We need to evaluate its value. We have to convert the base of the log into exponent so that we can evaluate its value. Otherwise, it would be difficult.
Therefore, we will use the formula logba=log10blog10ato find the required value.
Here we have to substitute a=2andb=6.
So, after substitution we get
log62=log106log102
Now we know that log102=0.693 and log106=1.7917.
Now on substituting the above values, we have
log62=1.79170.693
⇒log62=0.3868
Therefore, the value of log62 is 0.3868.
Additional information: Logarithmic Functions have some of the properties that allow you to simplify the logarithms when the input is in the form of product, quotient or the value taken to the power. Some of the properties are as follows:
(1) logbMN = logbM + logbN
Multiply two numbers with the same base, then add the exponents.
(2) logbNM = logbM − logbN
Divide two numbers with the same base, subtract the exponents.
(3) LogbMp= P logbM
Raise an exponential expression to power and multiply the exponents.
Note: In this question we can also convert loge6=loge2+loge3by using the property log(a×b)=loga+logb to make our question more easy. But I need to learn some values as we have used in this question. These are very used to values which are used frequently in questions of log functions.