Solveeit Logo

Question

Question: How do you evaluate \(f(-3)\) given \(f(x)=4{{x}^{3}}+{{x}^{2}}-5x?\)...

How do you evaluate f(3)f(-3) given f(x)=4x3+x25x?f(x)=4{{x}^{3}}+{{x}^{2}}-5x?

Explanation

Solution

To evaluate the given polynomial equation f(x)=4x3+x25xf(x)=4{{x}^{3}}+{{x}^{2}}-5x, we need to substitute the given value ofxxin the given polynomial equation provided, and then we have to compute the following polynomial equation with the given value of xx and the final value we get is the solution of the above given problem and the solution goes as follows
f(3)=4(3)3+(3)25(3)f(-3)=4{{(-3)}^{3}}+{{(-3)}^{2}}-5(-3)
Here the given xx value that is to be substituted in the polynomial equation is 3-3,and the polynomial expression is f(x)=4x3+x25xf(x)=4{{x}^{3}}+{{x}^{2}}-5x.

Complete step by step solution:
By substituting 3-3in the polynomial equation the equation look as follows:
By evaluating the equation found by substituting the value of xxi.e.3-3
We come across the following calculation,
That is,(3)3=27{{(-3)}^{3}}=-27
(3)2=9{{(-3)}^{2}}=9.
Substituting this value in the polynomial equation we get
f(3)=4(3)3+(3)25(3)f(-3)=4{{(-3)}^{3}}+{{(-3)}^{2}}-5(-3)
\Rightarrow 4×(27)+95×(3)4\times (-27)+9-5\times (-3)
By evaluating further,
\Rightarrow 108+9(15)-108+9-(-15)
\Rightarrow 108+9+15-108+9+15
\Rightarrow 108+24-108+24
\Rightarrow 84-84
Hence, from the above, we have successfully evaluated the given polynomial equation f(x)=4x3+x25xf(x)=4{{x}^{3}}+{{x}^{2}}-5xby substituting the given value of xx, that is 3-3and the solution we have found is 84-84.

Note: wWe can solve the given problem by the above method of substitution. Here, students may find difficulty in evaluating the exponent factor of a negative number as given in the above problem, one should be careful in assigning sign to the resulting value after evaluating the exponent part of the negative number. The student also may find difficulty in the adding after the evaluation of particular terms, one should be careful in that.