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Question: How do you evaluate \[{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}}\] using trigonometric funct...

How do you evaluate eπ4ie3π4i{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}} using trigonometric function?

Explanation

Solution

According to the given in the question we have to determine the value or evaluate eπ4ie3π4i{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}} using trigonometric function. So, to evaluate the given trigonometric function first of all we have to determine the value of the trigonometric term which eπ4i{e^{\dfrac{\pi }{4}i}}with the help of the formula as mentioned below:

Formula used:
eπ4i=cosπ4+isinπ4.................(A)\Rightarrow {e^{\dfrac{\pi }{4}i}} = \cos \dfrac{\pi }{4} + i\sin \dfrac{\pi }{4}.................(A)
Now, same as to evaluate the given trigonometric function we have to determine the value of the term of the given trigonometric function which is e3π4i{e^{\dfrac{{3\pi }}{4}i}}with the help of the formula as mentioned below:

e3π4i=cos3π4+isin3π4.................(B) \Rightarrow {e^{\dfrac{{3\pi }}{4}i}} = \cos \dfrac{{3\pi }}{4} + i\sin \dfrac{{3\pi }}{4}.................(B)
Now, as we have already obtained the values of the both of the terms with the help of the formulas (A) and (B) we have to substitute those values in that given trigonometric function to evaluate.
Now, to solve the obtained expression we have to use the formulas as mentioned below:

cosπ4=12...........(C) Sinπ4=12...........(D)  \Rightarrow \cos \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }}...........(C) \\\ \Rightarrow \operatorname{Sin} \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }}...........(D) \\\

Complete step by step answer:
Step 1: First of all we have to determine the value of the trigonometric term which eπ4i{e^{\dfrac{\pi }{4}i}}with the help of the formula (A) as mentioned in the solution hint. Hence,
eπ4i=cosπ4+isinπ4..................(1)\Rightarrow {e^{\dfrac{\pi }{4}i}} = \cos \dfrac{\pi }{4} + i\sin \dfrac{\pi }{4}..................(1)
Step 2: Now, same as the solution step 1 we have to evaluate the given trigonometric function we have to determine the value of the term of the given trigonometric function which is e3π4i{e^{\dfrac{{3\pi }}{4}i}}with the help of the formula (B) as mentioned in the solution hint. Hence,
e3π4i=cos3π4+isin3π4..................(2)\Rightarrow {e^{\dfrac{{3\pi }}{4}i}} = \cos \dfrac{{3\pi }}{4} + i\sin \dfrac{{3\pi }}{4}..................(2)
Step 3: Now, as we have already obtained the values of the both of the terms with the help of the formulas (A) and (B) we have to substitute those values in that given trigonometric functioneπ4ie3π4i{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}} to evaluate it. Hence, on substituting both of the expression (1) and (2) ineπ4ie3π4i{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}}.

cosπ4+isinπ4cos3π4+isin3π4 \Rightarrow \cos \dfrac{\pi }{4} + i\sin \dfrac{\pi }{4} - \cos \dfrac{{3\pi }}{4} + i\sin \dfrac{{3\pi }}{4}………………….(3)
Step 4: Now, we have to solve the expression (3) with the help of the formulas (C) and (D) which are as mentioned in the solution hint. Hence,
1+i21+i2\Rightarrow \dfrac{{1 + i}}{{\sqrt 2 }} - \dfrac{{ - 1 + i}}{{\sqrt 2 }}
On solving the expression as obtained just above,
=1+i+1i2 =22  = \dfrac{{1 + i + 1 - i}}{{\sqrt 2 }} \\\ = \dfrac{2}{{\sqrt 2 }} \\\

Hence, with the help of the formula (A), (B), (C), and (D) we have evaluated the given trigonometric expressioneπ4ie3π4i=22{e^{\dfrac{\pi }{4}i}} - {e^{\dfrac{{3\pi }}{4}i}} = \dfrac{2}{{\sqrt 2 }}.

Note: To evaluate the whole expression it is necessary that we have to evaluate the values of eπ4i{e^{\dfrac{\pi }{4}i}} and e3π4i{e^{\dfrac{{3\pi }}{4}i}} with the help of the formulas (A) and (B) which are mentioned in the solution hint.
We can determine the value of cos3π4\cos \dfrac{{3\pi }}{4} as be finding the value of cosπ4 - \cos \dfrac{\pi }{4}with the help of the formulas (C) and (D) as mentioned in the solution hint.