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Question: How do you evaluate \(\cos W=0.6157\)?...

How do you evaluate cosW=0.6157\cos W=0.6157?

Explanation

Solution

Now we are given with cosW=1.6157\cos W=1.6157 . We will make use of the inverse function of cos to write another equation in cos1{{\cos }^{-1}} . Now we will find the value of cos inverse and hence find the value of W.

Complete step by step answer:
Now let us first understand the trigonometric functions and inverse trigonometric functions.
Trigonometric function are nothing but ratios of a right angle triangle,
Now the given function cos is ratio of adjacent side and hypotenuse in a right angle triangle.
Hence cosθ\cos \theta gives us the value of the ratio for each angle θ\theta .
Now for each trigonometric ratio we have its inverse trigonometric function.
Inverse function of any function is nothing but a function which nullifies the effect of the function. Let us understand this by an example.
If f is a function such that f(x)=yf\left( x \right)=y then the function g is called the inverse function of f if g(y)=xg\left( y \right)=x for all values of x and y.
Now the inverse function of cos is denoted by cos1x{{\cos }^{-1}}x or arc cos .
Hence we can say that if cosθ=x\cos \theta =x then cos1x=θ{{\cos }^{-1}}x=\theta .
Now we are given with an equation cosW=0.6157\cos W=0.6157 .
Hence we can say that cos10.6517=W{{\cos }^{-1}}0.6517=W .
Now we calculating the value of cos10.6517{{\cos }^{-1}}0.6517 we get, cos10.6157=52{{\cos }^{-1}}0.6157={{52}^{\circ }} .
Hence the value of W is 52{{52}^{\circ }} .

Note:
Now note that the inverse function of f is generally denoted by f1{{f}^{-1}} . The negative power is just a notation and should not be considered as a fraction. Hence we can say f1(x)1f(x){{f}^{-1}}\left( x \right)\ne \frac{1}{f\left( x \right)} . Also it should be noted that inverse function of all functions need not exist. The functions will have an inverse function only if the function is bijective.