Question
Question: How do you evaluate \(\arccos \left( -\dfrac{1}{\sqrt{2}} \right)\)?...
How do you evaluate arccos(−21)?
Explanation
Solution
To solve the inverse trigonometric identity arccos(−21) then we need to remove the negative sign from the identity first of all. We have to apply the formula arccos(−x)=arccosx. This is done because arccos(−x) comes in the fourth quadrant and cosine is always positive in the first and the fourth quadrant. The inverse trigonometric identity arccos(x) could also be written as cos−1x.
Complete step by step solution:
We have our given identity that is arccos(−21).....(1).
We have to simplify the angle of the identity (1); we know that arccos(−x)=arccosx so, we have to write the identity arccos(−21) in another form such that, we get: