Solveeit Logo

Question

Question: How do you evaluate a function\(f\left( x \right)=x+7\) for a specific value\(f\left( -1 \right)\)?...

How do you evaluate a functionf(x)=x+7f\left( x \right)=x+7 for a specific valuef(1)f\left( -1 \right)?

Explanation

Solution

Function in mathematics is a rule by which each element of set A is associated with element of set B. It is a law which defines a relation between the independent variable (one variable) and dependent variable (one variable). A function relates inputs to outputs means a function is a machine in which we input something that gives us output , it is a relation where every input has exactly one output. A function is a relation between the domain and range such that value in the domain corresponds to only one value in the range.

Complete step by step solution:
When evaluating function notation the number in place of xx inf(x)f\left( x \right) is the number that you plug intoxx of your given function. In the given question the value of xx given is (1)\left( -1 \right).
Put this value of x=1x=-1in the given equationf(x)=x+7f\left( x \right)=x+7,we get
So, if f(x)=x+7f\left( x \right)=x+7 then f(1)f\left( -1 \right) is
f(1)=(1)+7 f(1)=6 \begin{aligned} & \Rightarrow f\left( -1 \right)=\left( -1 \right)+7 \\\ & \Rightarrow f\left( -1 \right)=6 \\\ \end{aligned}

Hence we get the value of x=1x=-1isf(1)=6f\left( -1 \right)=6

Note: We can also check that the above answer is correct or not.
Now what we will do, we will put this value of x=1x=-1 which is66 equals to the given equationf(x)=x+7f\left( x \right)=x+7,we get
f(x)=x+7=6  \begin{aligned} & \Rightarrow f\left( x \right)=x+7=6 \\\ & \\\ \end{aligned}
Now subtract 7-7 from both side of equation, we get
x+77=67 x=1 \begin{aligned} & \Rightarrow x+7-7=6-7 \\\ & \Rightarrow x=-1 \\\ \end{aligned}
Here we get x=1x=-1 which is given in the question. It means our answer is absolutely correct. In the given question f(1)f\left( -1 \right) does mean to inverse the out i.e. (–x-7). Thinking about the notations when solving an equation can lead to mistakes because functions have different notations. f(2)f\left( 2 \right) does not imply that function is multiplied by 2.