Solveeit Logo

Question

Question: How do you evaluate \({}^{6}{{C}_{4}}\)?...

How do you evaluate 6C4{}^{6}{{C}_{4}}?

Explanation

Solution

From the given question we have to evaluate the 6C4{}^{6}{{C}_{4}}. As we know that the combination means that the number of combinations of n objects taken r at a time is determined by the formula nCr=n!r!(nr)!{}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}. By expanding these factorials, we will get the solution.

Complete step by step answer:
From the question given we have been asked to evaluate the
6C4\Rightarrow {}^{6}{{C}_{4}}
As we know that the combination means that the number of combinations of n objects taken r at a time is determined by the formula
nCr=n!r!(nr)!\Rightarrow {}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}
By comparing here, we will get the
n=6\Rightarrow n=6
r=4\Rightarrow r=4
By substituting in the formula, we will get,
6C4=6!4!(64)!\Rightarrow {}^{6}{{C}_{4}}=\dfrac{6!}{4!\left( 6-4 \right)!}
By simplifying further, we will get
6C4=6!4!(2)!\Rightarrow {}^{6}{{C}_{4}}=\dfrac{6!}{4!\left( 2 \right)!}
As we know that expansion of factorial,
n!=n×(n1)×2×1\Rightarrow n!=n\times \left( n-1 \right)\ldots \times 2\times 1
From this we will expand the above,
6C4=6!4!(2)!\Rightarrow {}^{6}{{C}_{4}}=\dfrac{6!}{4!\left( 2 \right)!}
6C4=6×5×4!4!2\Rightarrow {}^{6}{{C}_{4}}=\dfrac{6\times 5\times 4!}{4!2}
By further simplification we will get,
6C4=15\Rightarrow {}^{6}{{C}_{4}}=15

Therefore, the evaluation of 6C4{}^{6}{{C}_{4}} is 1515.

Note: Students should know the formula of combination. Students should be aware of formulas of permutation and combination. the number of combinations of n objects taken r at a time is determined by the formula nCr=n!r!(nr)!{}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}. the number of permutations of n objects taken r at a time is determined by the formula npr=n!(nr)!{}^{n}{{p}_{r}}=\dfrac{n!}{\left( n-r \right)!}.