Question
Question: How do you evaluate \(^{10}{C_3} \)...
How do you evaluate 10C3
Solution
In order to evaluate the above ,consider n=10 and r=3 and use the formula of C(n,r)=nCr=r!(n−r)!n! to find the number of combinations.
Formula used:
C(n,r)=nCr=r!(n−r)!n!
p(n,r)=nPr=(n−r)!n!
Complete step by step solution:
Given 10C3 ,this is of the form nCr where n=10 and r=3.
To evaluate this we will use formula of C(n,r)=nCr=r!(n−r)!n!
So, Putting the value of n and r in the above formula
C(n,r)=nCr=3!(10−3)!10! =3!7!10!
10! is equivalent to 10×9×8×7!
=3!7!10×9×8×7! =3!7!10×9×8×7! =3×210×9×8 =10×3×4 =120
Therefore, value of 10C3 is equal to 120
Additional Information:
1.Factorial: The continued product of first n natural numbers is called the “n factorial “ and denoted
by n!.
2.Permutation: Each of the arrangements which can be made by taking some or all of number of
things are called permutations. If n and r are positive integers such that 1⩽r⩽n, then the number of all permutations of n distinct or different things, taken r at one time is denoted by the symbol
p(n,r)ornPr.
p(n,r)=nPr=(n−r)!n!
3.Combinations: Each of the different selections made by taking some or all of a number of objects
irrespective of their arrangement is called a combination. The combinations number of n objects, taken r at one time is generally denoted by
C(n,r)ornCr
Thus, C(n,r)ornCr= Number of ways of selecting r objects from n objects.
C(n,r)=nCr=r!(n−r)!n!
Note: 1. Factorials of proper fractions or negative integers are not defined. Factorial n defined only for whole numbers.
2.Meaning of Zero factorial is senseless to define it as the product of integers from 1 to zero. So, we
define it as 0!=1.
3.Don’t forget to cross-check your answer at least once as it may contain calculation errors.