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Question

Question: How do you divide \[\dfrac{{5 - i}}{{5 + i}}\] ?...

How do you divide 5i5+i\dfrac{{5 - i}}{{5 + i}} ?

Explanation

Solution

Here, we have to find the quotient of two complex numbers. We will first multiply the numerator and the denominator by the complex conjugate. Then we will use the algebraic identity and Foil method to simplify the expression in numerator and denominator. We will simplify the equation using the basic mathematical operations to get the required answer.

Formula Used:
The difference between the square numbers is given by the algebraic identity a2b2=(a+b)(ab){a^2} - {b^2} = \left( {a + b} \right)\left( {a - b} \right)

Complete Step by Step Solution:
We are given a complex number 5i5+i\dfrac{{5 - i}}{{5 + i}}.
Now, we will multiply the numerator and the denominator by the complex conjugate. Therefore, we get
5i5+i=5i5+i×5i5i\dfrac{{5 - i}}{{5 + i}} = \dfrac{{5 - i}}{{5 + i}} \times \dfrac{{5 - i}}{{5 - i}}
5i5+i=(5i)(5i)(5+i)(5i)\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{\left( {5 - i} \right)\left( {5 - i} \right)}}{{\left( {5 + i} \right)\left( {5 - i} \right)}}
The difference between the square numbers is given by the algebraic identity a2b2=(a+b)(ab){a^2} - {b^2} = \left( {a + b} \right)\left( {a - b} \right)
Now, by multiplying the numerators by using the FOIL method and the denominators by using the algebraic identity, we get
5i5+i=5(5i)i(5i)52i2\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{5\left( {5 - i} \right) - i\left( {5 - i} \right)}}{{{5^2} - {i^2}}}
Now, by multiplying each term in the expression, we get
5i5+i=255i5i+i252i2\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{25 - 5i - 5i + {i^2}}}{{{5^2} - {i^2}}}
Adding and subtracting the like terms, we get
5i5+i=2510i+i225i2\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{25 - 10i + {i^2}}}{{25 - {i^2}}}
We know that i2=1{i^2} = - 1. So, we get
5i5+i=2510i+(1)25(1)\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{25 - 10i + \left( { - 1} \right)}}{{25 - \left( { - 1} \right)}}
Again adding and subtracting the terms, we get
5i5+i=2410i26\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{24 - 10i}}{{26}}
Rewriting the expression, we get
5i5+i=242610i26\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{24}}{{26}} - \dfrac{{10i}}{{26}}
By simplifying the expression, we get
5i5+i=12135i13\Rightarrow \dfrac{{5 - i}}{{5 + i}} = \dfrac{{12}}{{13}} - \dfrac{{5i}}{{13}}

Therefore, the quotient of the complex number 5i5+i\dfrac{{5 - i}}{{5 + i}} is12135i13\dfrac{{12}}{{13}} - \dfrac{{5i}}{{13}}.

Note:
Here we need to keep in mind that the complex conjugate that is multiplied to both the numerators and the denominators should be the conjugate of the denominator. Also, if we are multiplying the complex conjugate, the conjugate should be taken only for the complex term. FOIL method is a method of multiplying the binomials by multiplying the first terms, then the outer terms, then the inner terms and at last the last terms. Thus, the product of two binomials is a trinomial.