Question
Question: How do you divide \(\dfrac{4-3i}{5+5i}\)?...
How do you divide 5+5i4−3i?
Solution
To divide the given fraction which is in the form of a complex number, we have to convert the denominator of the fraction into a real number by multiplying the number by the complex conjugate of the denominator.
Complete answer:
We have the given number as:
⇒5+5i4−3i
Now to get the denominator into the real form we must multiply it with the complex conjugate,
We know that for a complex number a+bi, the complex conjugate for that number is a−bi, where the terms aand bare real numbers.
Therefore, the complex conjugate of the number 5+5i will be 5−5i, therefore we will multiply the numerator and denominator of the number with the term 5−5i.
On multiplying we get:
⇒5+5i4−3i×(5−5i)(5−5i)
On multiplying we get:
⇒(5+5i)(5−5i)(4−3i)(5−5i)
Now on distributing the terms, we get:
⇒5×5−5×5i+5i×5−5i×5i4×5−4×5i−3i×5+3i×5i
On multiplying the terms, we get:
⇒25−25i220−35i+15i2
Now we know that the value of i2=−1, therefore on substituting in the equation, we get-
⇒25−25(−1)20−35i+15(−1)
On simplifying we get:
⇒25+2520−15−35i
⇒505−35i
Now on splitting the fraction, we get:
⇒505−5035i
On simplifying, we get:
⇒101−107i, which is the final answer in the form of a+bi where a=101 and b=−107 which are both real numbers.
Note:
it is to be remembered that whenever a complex number is multiplied with its complex conjugate, the complex part of the number is eliminated. It can be proved as:
(a+bi)(a−bi)=a2−abi+abi−b2i2
On simplifying we get:
(a+bi)(a−bi)=a2−b2i2
Now since the i2=−1 we can write the term as:
(a+bi)(a−bi)=a2+b2.
When we multiply and divide a number by a same number, the value of the fraction does not change, this is the reason we multiplied and divided the original term by the complex conjugate.