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Question

Question: How do you differentiate \[y = \sin {x^2}\]?...

How do you differentiate y=sinx2y = \sin {x^2}?

Explanation

Solution

Here, we have to find the derivative of the given function. We will differentiate the given function by using the chain rule and by using the derivative formula. Differentiation is a method of finding the derivative of the function and finding the rate of change of a function with respect to one variable.

Formula used:
We will use the following formulas:
Derivative formula: ddx(sinx)=cosx\dfrac{d}{{dx}}\left( {\sin x} \right) = \cos x
Derivative formula of Power rule: ddx(x2)=2x\dfrac{d}{{dx}}\left( {{x^2}} \right) = 2x

Complete Step by Step Solution:
We are given a function y=sinx2y = \sin {x^2}.
Now, by differentiating both sides of the given function with respect to xx, we get
dydx=ddx(sinx2)\Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\sin {x^2}} \right)
We know that if a function has two functions, then both the functions have to be differentiated separately.
We are given a trigonometric function of the sine of the algebraic function raised to the power 2. First, we will find the derivative of the trigonometric function and then the derivative of the algebraic function.
By using the derivative formula ddx(sinx)=cosx\dfrac{d}{{dx}}\left( {\sin x} \right) = \cos x and by using the chain rule, we get
dydx=cosx2ddx(x2)\Rightarrow \dfrac{{dy}}{{dx}} = \cos {x^2} \cdot \dfrac{d}{{dx}}\left( {{x^2}} \right)
Now using the derivative formula of Power rule ddx(x2)=2x\dfrac{d}{{dx}}\left( {{x^2}} \right) = 2x, we get
dydx=cosx22x\Rightarrow \dfrac{{dy}}{{dx}} = \cos {x^2} \cdot 2x
dydx=2x.cosx2\Rightarrow \dfrac{{dy}}{{dx}} = 2x.\cos {x^2}

Therefore, the derivative of y=sinx2y = \sin {x^2} is2xcosx22x\cos {x^2}.

Note: We have used the chain rule to find the derivative of the composite functions. Chain rule states that if a composite function f[g(x)]f\left[ {g\left( x \right)} \right] where f(x)f\left( x \right) and g(x)g\left( x \right) be two functions, then the derivative of the composite function isf[g(x)]g(x)f'\left[ {g\left( x \right)} \right] \cdot g'\left( x \right). If there is an arithmetic operation of addition and subtraction, then it appears as the same, but if no such arithmetic operation exists, then all these functions have to be the product of all the functions.