Question
Question: How do you differentiate \[y = \log {x^2}\] ?...
How do you differentiate y=logx2 ?
Solution
To solve the question given above, you need to know about logarithmic derivation. The logarithmic derivative of the initial function y=f(x) is the derivative of the logarithmic function. The derivatives of power-exponential functions, or functions of the form, can be computed effectively using this differentiation method. Where u(x) and v(x) are differentiable functions of x, y=u(x)v(x).
Formula used:
We will be using two approaches to solve the question mentioned above. The formulas required to solve the question using two different approaches are:
We can solve this question using the properties of logarithm. We know that logxn=nlogx.
In the second approach we will use the chain rule where: dxd(log(f(x)))=f(x)1×f′(x)
Complete step-by-step answer:
We are given: y=logx2
We will differentiate this function by using the laws of logarithm.
Now, using the first formula: logxn=nlogx
We get: y=2logx
On differentiating both sides with respect to x, we get:
dxdy=2×x1
=x2.
So, our final answer is x2
Additional information:
This question can also be solved using the chain rule:
We know that: dxd(log(f(x)))=f(x)1×f′(x)
On differentiating y=logx2 using the chain rule, we get:
dxdy=x21×dxd(x2)
$$
= \dfrac{1}{{{x^2}}} \times 2x \\
= \dfrac{2}{x} \\