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Question

Question: How do you differentiate \[y = \log {x^2}\] ?...

How do you differentiate y=logx2y = \log {x^2} ?

Explanation

Solution

To solve the question given above, you need to know about logarithmic derivation. The logarithmic derivative of the initial function y=f(x)y = f\left( x \right) is the derivative of the logarithmic function. The derivatives of power-exponential functions, or functions of the form, can be computed effectively using this differentiation method. Where u(x)u\left( x \right) and v(x)v\left( x \right) are differentiable functions of xx, y=u(x)v(x)y = u\left( x \right)v\left( x \right).

Formula used:
We will be using two approaches to solve the question mentioned above. The formulas required to solve the question using two different approaches are:
We can solve this question using the properties of logarithm. We know that logxn=nlogx\log {x^n} = n\log x.
In the second approach we will use the chain rule where: ddx(log(f(x)))=1f(x)×f(x)\dfrac{d}{{dx}}\left( {\log \left( {f\left( x \right)} \right)} \right) = \dfrac{1}{{f\left( x \right)}} \times f'\left( x \right)

Complete step-by-step answer:
We are given: y=logx2y = \log {x^2}
We will differentiate this function by using the laws of logarithm.
Now, using the first formula: logxn=nlogx\log {x^n} = n\log x
We get: y=2logxy = 2\log x
On differentiating both sides with respect to x, we get:
dydx=2×1x\dfrac{{dy}}{{dx}} = 2 \times \dfrac{1}{x}
=2x= \dfrac{2}{x}.
So, our final answer is 2x\dfrac{2}{x}
Additional information:
This question can also be solved using the chain rule:
We know that: ddx(log(f(x)))=1f(x)×f(x)\dfrac{d}{{dx}}\left( {\log \left( {f\left( x \right)} \right)} \right) = \dfrac{1}{{f\left( x \right)}} \times f'\left( x \right)
On differentiating y=logx2y = \log {x^2} using the chain rule, we get:
dydx=1x2×ddx(x2)\dfrac{{dy}}{{dx}} = \dfrac{1}{{{x^2}}} \times \dfrac{d}{{dx}}\left( {{x^2}} \right)
$$
= \dfrac{1}{{{x^2}}} \times 2x \\
= \dfrac{2}{x} \\

The final answer is $$\dfrac{2}{x}$$. **Note:** While solving questions similar to the one given above, remember the chain rule is a method for determining the derivative of composite functions, with the number of functions in the composition determining the number of differentiation steps required. Consider an example: $$f\left( x \right) = \left( {goh} \right)\left( x \right) = g\left( {h\left( x \right)} \right)$$then this becomes $$f'\left( x \right) = g'\left( {h\left( x \right)} \right) \times h'\left( x \right)$$. Since the composite function f is made up of two functions, g and h, you must differentiate $$f\left( x \right)$$ using the derivatives $$g'$$ and $$h'$$.