Question
Question: How do you differentiate \[y = \ln {x^2}\]?...
How do you differentiate y=lnx2?
Solution
We have given a function which is equal to a logarithmic of x2. We have to find its derivative. Since the variable in the function is x, we differentiate the function with respect to ‘x’. Firstly, we take derivatives on both sides; the derivative of log of x is x1, we use this property and differentiate. Then, we take the derivative of x2 which will be in the product, since derivative of xn is nxn−1, so we use this property. Then, we simplify the result and we get the answer.
Complete step by step solution:
The given function is y=lnx2, we have to find its derivative.
Differentiating both sides with respect to ‘x’
⇒dxd(y)=dxd(lnx2)
Since the derivative of logx is x1.
⇒dxdy=x21⋅dxd(x2)
Now derivative of xn is nxn−1dx, so
⇒dxdy=x21⋅2×x⋅dxdx
⇒dxdy=x22x
⇒dxdy=x2
So, dxdy=x2
Derivative of y=lnx2 is x2.
Note:
In mathematics, logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b must be raised to produce that number x. In the simplest case, the logarithm counts the number occurrences of the same factor in repeated multiplication, example: Since ⇒1000=10×10×10=103.
The logarithm base 10 of 1000 is 3 or log10(1000)=3. The logarithm of x base b is denoted as logb(x), or without parenthesis, logbx or without explicit base logx.
Generally, exponentiation allows any positive real number as base to be raised to any real power, always producing positive results. So, logb(x), for any two positive real number b and x, where b is not equal to 1 is always unique real number y.
Let us have a function y=f(x) of variable x. The derivative of the function is the measure of the rate at which the value y of the function changes with respect to the variable x.