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Question

Question: How do you differentiate \( y = 2{e^x}? \)...

How do you differentiate y=2ex?y = 2{e^x}?

Explanation

Solution

Hint : As we know that to differentiate means to find the derivative of independent variable value which changes the value of the function. Let a function be y=f(x)y = f(x) , where yy is a function of xx . Any change in the value of yy due to the change in the value of xx will be written as dydx\dfrac{{dy}}{{dx}} . This is the general expression of the derivative of a function.

Complete step-by-step answer :
The derivative of the second part ex{e^x} is itself only, it is Euler’s number and we know that ddx(ex)=ex\dfrac{d}{{dx}}({e^x}) = {e^x} and the constant part just comes out of the derivative.
So we have
ddx[2ex]=2ddx[ex]\dfrac{d}{{dx}}[2{e^x}] = 2\dfrac{d}{{dx}}[{e^x}] , as the constant part comes out which gives us dydx=2ex\dfrac{{dy}}{{dx}} = 2{e^x} .
We have nothing to do with chain rule here because if we further change it in the term uu and ddx(eu)=eu(dudx)\dfrac{d}{{dx}}({e^u}) = {e^u}(\dfrac{{du}}{{dx}}) but we know that u(x)=xu(x) = x and dudx=1\dfrac{{du}}{{dx}} = 1 , so at last we get
ddx(ex)=ex1=ex\dfrac{d}{{dx}}({e^x}) = {e^x}*1 = {e^x} .
It gives the same result. We do not need to apply chain rule here.
Hence the differentiation of y=2exy = 2{e^x} is 2ex2{e^x} .
So, the correct answer is “ 2ex2{e^x} ”.

Note : We should know that ex{e^x} is an exponential function and the base of this function is e,e, Euler’s number which is the only function that remains unchanged when differentiated. It is an irrational number and is approximately 2.71822.7182 . In the above question 22 is a constant and any constant which is multiplied by a variable remains the same when taking a derivative. We should first understand what is asked in the question and then proceed to differentiate the function in the right way to get the correct answer.