Question
Question: How do you differentiate \(f(x) = \tan (\ln x)\) using the chain rule?...
How do you differentiate f(x)=tan(lnx) using the chain rule?
Solution
This question is from the topic of differentiation. In this question we need to find the derivative of function f(x)=tan(lnx) using the chain rule. To solve this question we need to know the conditions of chain rule of differentiation and the derivative of functions tanx and lnx.
Complete step by step answer:
Let us try to solve this question in which we are asked to find the derivative of function f(x)=tan(lnx). Before differentiating this, let’s have a look at definition of chain rule, suppose a function f(x)=g(h(x)) such that both g and h are differentiable with respect to x then f is also differentiable and its differentiation is given by f′(x)=g′(h(x))⋅h′(x) where f′(x)=dxd(f(x)) and similarly g′ and h′ are derivatives of functions g and hrespectively.
Now, let’s find the derivative of functionf(x)=tan(lnx). Function to derive f(x)=tan(lnx) is composition of differentiable functions ln(x) andtanx. So for the derivative of the function f(x)=tan(lnx) we can use the chain rule of differentiate. After applying chain rule to function f(x)=tan(lnx), we get
dxd(tan(lnx))=dxd(tan(lnx))⋅dxd(lnx) eq(1)
As we know that dxd(tanx)=sec2x. So we have,
dxd(tan(lnx))=sec2(lnx) eq(2)
And, also we know that dxd(lnx)=x1. So we have,
dxd(lnx)=x1 eq(3)
Now, putting back the value of eq(2) and eq(3)ineq(1), we get the derivative ofln(5x).Hence the derivative of function
dxd(tan(lnx))=sec2(lnx)⋅x1 ∴dxd(tan(lnx))=xsec2(lnx)
Note: To solve these types of questions in which we are asked to find the derivative of a given function. For solving this type of question we are required to have knowledge of how to find derivatives of a function, differentiability of common function and properties of differentiation such sum rule, product rule, division rule and chain rule.