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Question

Question: How do you differentiate \(4xy-3x-11=0\)?...

How do you differentiate 4xy3x11=04xy-3x-11=0?

Explanation

Solution

To solve the given question we will use the concept of implicit differentiation. We will differentiate the given equation with respect to x. In order to differentiate the equation we will use the product rule and power rule of the differentiation.

Complete step by step solution:
We have been given an equation 4xy3x11=04xy-3x-11=0.
We have to differentiate the given equation.
Now, differentiating the given equation with respect to x we will get
ddx(4xy)ddx3xddx11=ddx0\Rightarrow \dfrac{d}{dx}\left( 4xy \right)-\dfrac{d}{dx}3x-\dfrac{d}{dx}11=\dfrac{d}{dx}0
Now, we know that ddx(uv)=uddxv+vddxu\dfrac{d}{dx}\left( uv \right)=u\dfrac{d}{dx}v+v\dfrac{d}{dx}u and ddxxn=nxn1\dfrac{d}{dx}{{x}^{n}}=n{{x}^{n-1}}
Now, applying the differentiation rules to the above obtained equation we will get
4(xddxy+yddxx)30=0\Rightarrow 4\left( x\dfrac{d}{dx}y+y\dfrac{d}{dx}x \right)-3-0=0
Now, simplifying the above obtained equation we will get
4(xdydx+y)3=0 4xdydx+4y=3 4xdydx=34y \begin{aligned} & \Rightarrow 4\left( x\dfrac{dy}{dx}+y \right)-3=0 \\\ & \Rightarrow 4x\dfrac{dy}{dx}+4y=3 \\\ & \Rightarrow 4x\dfrac{dy}{dx}=3-4y \\\ \end{aligned}
Now, to find the value of dydx\dfrac{dy}{dx} we need to rearrange the terms in the above obtained equation. Then we will get
dydx=34y4x\Rightarrow \dfrac{dy}{dx}=\dfrac{3-4y}{4x}
Hence above is the required solution of the given equation.

Note: In this particular question we are assuming that the y is the function of x so we use the concept of implicit differentiation to solve further. If students consider the y as a constant and solve accordingly they will get the incorrect solution. Alternatively we can simplify the equation and convert it into the function of x alone and then differentiate the equation.
We can rewrite the given equation as
4xy3x11=0 4xy=11+3x y=3x+114x \begin{aligned} & \Rightarrow 4xy-3x-11=0 \\\ & \Rightarrow 4xy=11+3x \\\ & \Rightarrow y=\dfrac{3x+11}{4x} \\\ \end{aligned}
Now, using the quotient rule of the differentiation we can solve the equation and get the desired answer.