Question

How do you determine which ordered pair is a solution of y = 4x + 2?

Answer 1

We will first look at some examples which fits the given linear equation nicely so that we get an idea how to find the ordered pairs.

Complete step-by-step answer:
We are given that we need to determine how to find ordered pairs which satisfy the equation
y = 4x + 2.
Let us first look at some examples to determine the same.
If we put x = 0 in the given equation “y = 4x + 2”, then we will get y = 0 + 2 = 2.
So, when x = 0, then y = 2.
Now, if we put x = 1 in the given equation “y = 4x + 2”, then we will get y = 4 + 2 = 6.
So, when x = 1, then y = 6.
Now, we see that if we need the ordered pair to be the solution of the given equation “y = 4x + 2”, then the x and y both together must satisfy the given equation.

Hence, when we need to determine whether some ordered pair satisfies the given equation or not, we just need to put the values of x and y and see whether they are giving an accurate answer or not.

Note:
The students must note that: If you are given that you need to check whether (a, b) is a solution of the given equation “y = 4x + 2”, then we just need to put x = a and y = b.
For example:- If we want to see if (5, 10) is a solution of “y = 4x + 2” or not.
We will put x = 5 in the right hand side of the equation to get: RHS = 4(5) + 2 = 20 + 2 = 22
Now, we will put y = 10 in left hand side of the equation to get: LHS = 10
Since, 10 and 22 are not equal, therefore, (5, 10) is not a solution of the given equation.