Question
Question: How do you determine the mass of carbon dioxide produced when \(0.85g\) of butane reacts with oxygen...
How do you determine the mass of carbon dioxide produced when 0.85g of butane reacts with oxygen according to the following equation?
2C4H10+13O2→8CO2+10H2O
Solution
Here we have reaction of butane C4H10 with oxygen O2 so mainly it is a combustion reaction which gives carbon dioxide CO2 and water. Thus for finding out the amount of carbon dioxide produced from 0.85g of butane we first have to find out the amount of carbon dioxide forming according to the reaction.
Complete step-by-step answer: According to the reaction we have 2C4H10+13O2→8CO2+10H2O in which if we consider the molar mass of butane, it is 58g and as there are 2moles of butane therefore we can say that we have a total of 116g . So, 116g of butane is reacting with oxygen and forming carbon dioxide and water. Amount of carbon dioxide is 44g as there is a number 8 in stoichiometry hence, we can say a mass of 352g is produced.
Mass of butane =116g
Mass of carbon dioxide =352g
2C4H10+13O2→8CO2+10H2O
116gofC4H10produces=352gCO2
Thus for one gram of butane we will get the amount of carbon dioxide as 1gofC4H10produces=116g352gCO2
Now for the amount we want is for 0.85g of butane, thus it will be-
0.85gofC4H10produces(116g352g×0.85)CO2
=2.579gCO2
On solving we get, 2.579g of carbon dioxide is forming from 0.85g of butane.
Note: As we calculated for carbon dioxide, we can easily find out the amount of other substances formed from the reaction of butane and oxygen. The same reaction question can be asked for the amount of water produced and also for the amount of oxygen needed for the reaction. The combustion reactions are when any hydrocarbon reacts with full supply of air oxygen and produces carbon dioxide and water at the end as products.