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Question

Question: How do you convert \(xy = 1\) into polar form?...

How do you convert xy=1xy = 1 into polar form?

Explanation

Solution

In this problem, we have given an equation in the rectangular coordinates. Here we are asked to convert the given rectangular form equation into the polar form. To convert the given equation into the polar form we need to use some identities and by using that identity we can get the required solution.

Formula used:
Half angle property of sine function: sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta

Complete step by step solution:
We are given the following equation in rectangular coordinates:
xy=1xy = 1…(i)
We are to find the equivalent polar coordinates.
The relation between rectangular coordinates (x,y)\left( {x,y} \right) and polar coordinates (r,θ)\left( {r,\theta } \right) is as follows:
x=rcosθx = r\cos \theta …(ii)
y=rsinθy = r\sin \theta …(iii)
Substituting the values of xx and yy from equation (ii) and (iii) in equation (i), we get
xy=1xy = 1
(rcosθ)(rsinθ)=1\Rightarrow \left( {r\cos \theta } \right)\left( {r\sin \theta } \right) = 1
Multiply the terms, we get
r2cosθsinθ=1\Rightarrow {r^2}\cos \theta \sin \theta = 1
Now, use the half angle property of the sine function, sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta in the above equation.
r2×sin2θ2=1\Rightarrow {r^2} \times \dfrac{{\sin 2\theta }}{2} = 1
Multiply both sides of the equation by 22, we get
r2sin2θ=2\Rightarrow {r^2}\sin 2\theta = 2

Hence, the required equivalent polar equation is r2sin2θ=2{r^2}\sin 2\theta = 2.

Additional information:
In two dimensions, the Cartesian coordinate (x,y)\left( {x,y} \right) specifics the location of a point P in the plane. A polar coordinate system in a plane consists of a fixed point OO, called the pole (or origin), and a ray emanating from the pole, called the polar axis. In such a coordinate system we can associate with each point PP in the plane a pair of polar coordinates (r,θ)\left( {r,\theta } \right), where rr is the distance from PP to the pole and θ\theta is an angle from the polar axis to the ray OPOP. The number rr is called the radical coordinate of PP and the number θ\theta the angular coordinate (or polar angle) of PP.

Note: In this problem our aim is to convert the given polar coordinate equation which is in the form (r,θ)\left( {r,\theta } \right) into rectangular coordinates, for this we followed some important steps.
Relationship between Polar and Rectangular Coordinates:
Frequently, it will be useful to superimpose a rectangular xyxy-coordinate system on top of a polar coordinate system, making the positive xx-axis coincide with the polar axis. If this is done, then every point P will have both rectangular coordinates (x,y)\left( {x,y} \right) and polar coordinates (r,θ)\left( {r,\theta } \right). These coordinates are related by the equations
x=rcosθx = r\cos \theta , y=rsinθy = r\sin \theta …(1)
These equations are well suited for finding xx and yy when rr and θ\theta are known. However, to find rr and θ\theta when xx and yy are known, it is preferable to use the identities sin2θ+cos2θ=1{\sin ^2}\theta + {\cos ^2}\theta = 1 and tanθ=sinθ/cosθ\tan \theta = \sin \theta /\cos \theta to rewrite (1) as
r2=x2+y2{r^2} = {x^2} + {y^2}, tanθ=yx\tan \theta = \dfrac{y}{x}…(2