Question

How do you convert benzene to bromobenzene

Answer 1

We have to know that in organic chemistry benzene is one of the important compounds. It is one of the aromatic compounds. The molecular formula of benzene is ${{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}$. Bromobenzene is one of the derivatives of benzene. Bromo benzene is one of the electrophilic substitution compounds in benzene.

Complete answer:
The molecular formula of benzene is ${{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}$.
The molecular formula of bromobenzene is ${{\text{C}}_{\text{6}}}{{\text{H}}_5}{\text{Br}}$.
The structural formula of benzene is

The structural formula of bromobenzene is

The conversion of benzene to bromobenzene.
The molecular formula of ferric chloride is ${\text{FeC}}{{\text{l}}_{\text{3}}}$.
Benzene reacts with chlorine molecules in presence of ferric chloride to give the product of bromobenzene. Here ferric chloride acts as the catalyst.
The reaction for the above discussion is given below,
${{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}} + {\text{C}}{{\text{l}}_{\text{2}}}\xrightarrow{{FeC{l_3}}}{{\text{C}}_{\text{6}}}{{\text{H}}_5}{\text{Br}}$

According to the above discussion and reaction scheme, we conclude conversion of benzene to bromobenzene by using chlorine as reactant and ferric chloride act as catalyst.

Note:
We also need to know that bromo benzene is one of the mono substituent benzene compounds. Each mono-substituent moiety having three named positions in the ring. In the ring a nearby mono substituent group is called an ortho position, that means two ortho positions are in the ring, because of the left and right side of the substituent group. The alternatively position of the substituent group in the ring is called meta position, here also two meta positions possible in the left and right side of the substituent group. Para position is nothing but directly opposite to the substituent group in the ring. Electrophilic substitutions are attacked in ortho and para position in the ring.