Question

How do you calculate the ionic strength of $0.0087M$ $NaOH$?

Answer 1

There are many types of bonding through which the elements and compounds interact in the chemical world namely the ionic bond, the covalent bond etc. The ionic bonds are usually stronger than that of covalent bonds but in the form of the networked covalent molecule, the compound is pretty strong in comparison.

Complete step by step answer:
The ionic bond is much stronger than the covalent bonds in terms of the strength but the covalent bonds when exhibit and increased strength in the form of crystal occur in the form of a network usually.
The compounds that form covalent bonds usually tend to form a network of bonds to achieve strength and stability. These are characterised as hard and brittle compounds like silicon carbide or diamond. These compounds consist of a large number of atoms of the constituent elements and which are connected to each other in a network of chemical covalent bonds.
The ionic strength of the compound can be calculated as the molar ionic strength
The molar ionic strength is calculated as, I, and is the function of the concentration of that solution
$I = \dfrac{1}{2}\sum\nolimits_{i = 1}^n {{c_i}{z_i}^2}$
Here c is the molar concentration of the ion in inspection and z is the charge on that ion and the sum of them are taken for all ions in the compound or solution.
So, $I = \dfrac{1}{2}[0.0087 \times {( + 1)^2} + 0.0087 \times {( - 1)^2}] = 0.0087mol/L$
This is how we can calculate the ionic strength.

Note: In Chemistry, there are three types of substances namely the acidic, basic, and neutral. It all is related to the amount of hydrogen ion that the compound can generate. The acidic substance turns moist litmus paper bred and the basic ones turn the litmus paper blue. The compounds which are neutral don't affect the litmus paper.