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Question: How do you calculate derivatives?...

How do you calculate derivatives?

Explanation

Solution

We first explain the form of derivative with respect to the slope. We express the mathematical form with both dydx\dfrac{dy}{dx} and slope=ΔyΔxslope=\dfrac{\Delta y}{\Delta x}. We then represent the small changes for the limit theorem of derivative. We understand the concept better with an example.

Complete step-by-step solution:
Let us take a function in the form of y=f(x)y=f\left( x \right). We try to find the slope of the curve at a particular point of (a,b)\left( a,b \right) which is on the curve.
The slope will be considered as the unit change of yy with respect to change of xx.
The mathematical representation will be done for small changes where the slope becomes dydx\dfrac{dy}{dx}.
We can also express it as slope=ΔyΔxslope=\dfrac{\Delta y}{\Delta x}. The derivative of a function is the rate at which the function value is changing, with respect to x, at a given value of x.
For the point (a,b)\left( a,b \right), the slope will be [dydx](a,b){{\left[ \dfrac{dy}{dx} \right]}_{\left( a,b \right)}}.
This representation of dydx\dfrac{dy}{dx} is called the derivative form.
Let us take an example where we take f(x)=logxf\left( x \right)=\log x. The slope or derivative form of the function gives dydx=f(x)=1x\dfrac{dy}{dx}={{f}^{'}}\left( x \right)=\dfrac{1}{x}.
For the point (1,1)\left( 1,1 \right), the slope will be [dydx](1,1)=[1x](1,1)=1{{\left[ \dfrac{dy}{dx} \right]}_{\left( 1,1 \right)}}={{\left[ \dfrac{1}{x} \right]}_{\left( 1,1 \right)}}=1.

Note: The derivative has a limit definition for slope=ΔyΔxslope=\dfrac{\Delta y}{\Delta x}. The function changes from y1=f(x){{y}_{1}}=f\left( x \right) to y2=f(x+h){{y}_{2}}=f\left( x+h \right) where h0h\to 0.
So, slope=ΔyΔx=limh0f(x+h)f(x)hslope=\dfrac{\Delta y}{\Delta x}=\displaystyle \lim_{h \to 0}\dfrac{f\left( x+h \right)-f\left( x \right)}{h}.