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Question: How do we write the given expression in terms of \(i\) : \(\sqrt { - 45} \) ?...

How do we write the given expression in terms of ii : 45\sqrt { - 45} ?

Explanation

Solution

To solve this question, first we will try to observe the given expression by removing the negative sign from the expression, and then we will discuss the term how 1\sqrt { - 1} is related to ii. And finally, simplify the positive square root expression to get the final answer.

Complete step by step solution:
The given special symbol, ii, is used to represent the square root of negative 1, 1\sqrt { - 1} .
As we know, there is no such thing in the real number universe as the 1\sqrt { - 1} because there are no two identical numbers that we can multiply together to get -1 as the exact solution.
1.1=11.1 = 1 and 1.1 - 1. - 1 is also 1. Obviously 1.1=11. - 1 = - 1 , but 1 and -1 are not the same number. They both have the same magnitude(distance from zero), but they are not identical.
So, when we have a number that involves a negative square root, math developed a plan to get around that problem by saying that anytime we run across that issue, we make our number positive so we can deal with it and put an ii at the end.
So, in this case:
45 =45×1   \sqrt { - 45} \\\ = \sqrt {45} \times \sqrt { - 1} \\\ \\\
As i=1i = \sqrt { - 1} :
45=45i\therefore \sqrt { - 45} = \sqrt {45} i
Since, 45=9×545 = 9 \times 5 , the answer can be simplified to:
45i=9.5i=35i\because \sqrt {45} i = \sqrt {9.5} i = 3\sqrt 5 i

Hence, the given expression in terms of ii is 35i3\sqrt 5 i.

Note:
Iota, ii, is a Greek letter that is widely used in mathematics to denote the imaginary part of a complex number. Let's say we have an equation: x2+1=0{x^2} + 1 = 0 . In this case, the value of xx will be the square root of -1, which is fundamentally not possible.