Question
Question: How do we calculate the number of sodium ions, \(N{a^ + }\) , in \(14.2g\) of sodium sulphate? [Rela...
How do we calculate the number of sodium ions, Na+ , in 14.2g of sodium sulphate? [Relative atomic masses Na=23,S=32,O=16 ]?
Solution
To solve this question, first we will calculate the molar mass of sodium sulphate, then we will find the number of moles present in it. And, finally with the help of no. of moles in sodium sulphate, we can find the number of sodium ions present in 14.2g of sodium sulphate.
Complete step-by-step answer: sodium sulphate.First, we will write the chemical formula of Sodium Sulphate, which is Na2SO4 .
To find the number of sodium ions in sodium sulphate, first we have to calculate the total number of moles of Sodium Sulphate in a sample.
Here, we have the formula to calculate the number of moles of any compound:
No.ofmoles=molarmassofthecocompoundmassofthecompound
In the above formulae, we have already given the mass of the Sodium Sulphate. But we don’t know the molar mass of the Sodium Sulphate.
So, the Molar mass of sodium sulphate is as:
MolarMass=atomicmassingrams=2(23)+32+4(16)=142gramspermole
Now, we have the molar mass of Sodium Sulphate, so we can find the number of Moles:
No.ofmoles=142gmol−114.2g=0.1mol
Now, for every 1mol of Na2SO4 we have 2moles of Na+ ions.
Multiply the moles of Na2SO4 that we found just then by 2 to obtain the moles of sodium ions.
As we know, 6.022×1023 is the number of particles or ions in 1mole of any substance. We use Avogadro’s Number to find the number of ions present in any compound.
So, In 1mole of Na2SO4 , 6.022×1023 number of ions are present.
∴ In 0.2mole of Na2SO4 , 6.022×1023×0.2mol number of ions are present, which is 1.2044×1023ions .
Hence, 1.2044×1023ions number of sodium ions, Na+ , present in 14.2g of
Note: A mole of a substance or a mole of particles is defined as containing exactly 6.022×1023particles , which may be atoms, molecules, ions, or electrons. This is an experimentally obtained value.