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Question

Question: How do I solve \[\ln \left( {{e}^{x}} \right)\] ?...

How do I solve ln(ex)\ln \left( {{e}^{x}} \right) ?

Explanation

Solution

In this question here a function ln\ln which is actually a logarithmic function with it’ base ee where ee is the exponential constant also lnv\ln v is written as logev{{\log }_{e}}v is and we know the properties of log\log and one of the property is ln(ab)=bln(a)\ln ({{a}^{b}})=b\ln (a) and when we apply this in given question we get only xx.

Complete step by step solution:
As the given function is ln(ex)\ln \left( {{e}^{x}} \right) as it is already solved we just need to simplify it.
Just recall the property of log\log that is
ln(ab)=bln(a)\Rightarrow \ln ({{a}^{b}})=b\ln (a)
Now compare it with a given function
a=e , b = x\Rightarrow a=e\text{ , b = x}
ln(ex)=xlne\Rightarrow \ln \left( {{e}^{x}} \right)=x\ln e
And lne\ln e can also be written as logee{{\log }_{e}}e
xlogee\Rightarrow x{{\log }_{e}}e
Also, we know that value of log\log function with the same base value is 11
x\Rightarrow x

Hence the simplified value of ln(ex)\ln \left( {{e}^{x}} \right) is xx.

Note: On solving these types of questions first write down the function and look it carefully and recall the properties of that function just in this question logarithm recall the properties of the log then you will be able to solve or simplify.