Question

How do I find oxidation number (s) on the periodic table?

Answer 1

To figure out how to discover the oxidation number of an iota in a given compound, it is imperative to realize what oxidation numbers are. The oxidation number of a particle is a number that addresses the all-out number of electrons lost or acquired by it

Complete answer:
For metals on the left side of the periodic table the family number often gives the oxidation number
I A = + 1

II A = +2

III A = + 3

IV A = + 4 but can also be + 2 , -2 and -4.

V A = + 5 but can also be +3, and -3 (count to the right to find the number of negative electrons -e needed to become an inert gas.)

VI A = + 6 can also be + 4 ,+2 but is more usually -2

VII A = + 7 can also be +5, +3 +1 but is usually -1

VIII A = 0 This family is the inert gases that do not want to lose or gain electrons,
The transition metals can be very confusing in terms of oxidation number because of movement between the s and d orbitals.
IB = +1 but also can be +2

II B = +2 almost always +2

III B = +3

IV B = +4 but also +2

V B = +5 but also + 3 and +2

VI B = +6 but also +4, + 3 and +2 (Chromium means color because each of the different oxidation numbers creates a different color.)

VII B = +7 but also + 5 +3, +2

VIII B = + 3 and +2

IX B = + 3 and + 2

X B = +3 and + 2

Note: A few components in the occasional table have just a single oxidation number or two oxidation numbers. Be that as it may, some have a great deal of oxidation numbers. The oxidation number of components in a compound can be positive or negative or perhaps zero.