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Question: How do I find missing values in binomial expansions?...

How do I find missing values in binomial expansions?

Explanation

Solution

The term of the form (a+b)n{{\left( a+b \right)}^{n}} is called a binomial term. In the expansion of this binomial, there are total n+1 terms. The (r+1)th term of the expansion of the binomial expansion is nCrarbnr^{n}{{C}_{r}}{{a}^{r}}{{b}^{n-r}}. We can find the binomial term by substituting the values of a, b, and n in this general term. It should be noted that here nn is a positive integer. To solve the given problem, we will assume a binomial expansion and find its missing term using the information given above.

Complete step by step solution:
Let’s assume we are given the expansion of the binomial as (1+2x)a=b+8x+cx2+32x3+16x4{{\left( 1+2x \right)}^{a}}=b+8x+c{{x}^{2}}+32{{x}^{3}}+16{{x}^{4}}. We need to find the missing terms.
As the highest power in the expansion on the right-hand side is 4. The power of the term on the left-hand side must be also 4. Hence, we get a=4a=4.
The first term on the right side is a constant term. The only constant term we can get from the binomial on the left side is 1. Hence, we get b=1b=1.
We want to find the coefficient of x2{{x}^{2}}. It is third term on the right side, so its coefficient will be 4C2×22=24^{4}{{C}_{2}}\times {{2}^{2}}=24. Hence, we get c=24c=24.
In this way, using the binomial and its expansion we can find their missing terms.

Note: We can use more special binomial expansions to expand the series. If one of the terms inside the bracket is 1. then, we can use the expansion of (1+x)n{{\left( 1+x \right)}^{n}} whose general form of expansion is r=0nnCrxr\sum\limits_{r=0}^{n}{^{n}{{C}_{r}}{{x}^{r}}}. For these types of problems, these expansions are very important and should be remembered.
We can use these expansions only when nn is a positive integer. For cases when the nn is a non-positive integer, we need to use different types of expansions.