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Question: How can you find the domain and range of exponential functions \(f(x) = 2 - {e^{\dfrac{x}{2}}}\)?...

How can you find the domain and range of exponential functions f(x)=2ex2f(x) = 2 - {e^{\dfrac{x}{2}}}?

Explanation

Solution

We will first find out the possible values of x we can put in the function, the set of those values of x will be known as the domain of the given function. Now, the possible values of f (x) will be the range of the given function.

Complete step-by-step solution:
We are given that we are required to find the domain and range of exponential functions f(x)=2ex2f(x) = 2 - {e^{\dfrac{x}{2}}}.
Now, we know that in exponential functions, power can be anything and can take any value.
Therefore, x2R\dfrac{x}{2} \in \mathbb{R}, which will then imply that xRx \in \mathbb{R}.
Thus, its domain is whole of real numbers.
Hence, Domain = R\mathbb{R}.
Now, since we know that eu>0{e^u} > 0 for all uRu \in \mathbb{R}.
Therefore, we have ex2>0{e^{\dfrac{x}{2}}} > 0
Multiplying by – 1 on both the sides of above equation, we will then obtain the following equation with us:-
ex2<0\Rightarrow - {e^{\dfrac{x}{2}}} < 0
Adding 2 on both the sides of the above mentioned equation, we will then obtain the following equation with us:-
2ex2<0+2\Rightarrow 2 - {e^{\dfrac{x}{2}}} < 0 + 2
Simplifying the right hand side of the above equation, we will then obtain the following equation with us:-
2ex2<2\Rightarrow 2 - {e^{\dfrac{x}{2}}} < 2
Thus, the range of the given function is (,2)\left( { - \infty ,2} \right).
Hence, the final answer is as follows: Range = (,2)\left( { - \infty ,2} \right) and Domain = R\mathbb{R}.

Note: The students must know the definitions of both the Domain and Range before pursuing any question to find them. If we need to find the domain and range of a function f (x), the domain is the set of possible values of x which can be put in the function and the possible values of f (x) which comes out will be the range of the function.
The students must also note that we have a strictly less than sign in the solution of the above question, therefore, we used the open bracket instead of a closed one. And, thus we have the open brackets on both the sides of the interval (,2)\left( { - \infty ,2} \right).