Question

How are the following conversions carried out?

(i)Propene$\rightarrow$Propan-2-ol.

(ii)Benzyl chloride$\rightarrow$Benzyl alcohol.

(iii)Ethyl magnesium chloride$\rightarrow$Propan-1-ol.

(iv)Methyl magnesium bromide$\rightarrow$2-Methylpropan-2-ol.

Answer 1

(i)If propene is allowed to react with water in the presence of an acid as a catalyst,then propan-2-ol is obtained.

(ii)If benzyl chloride is treated with NaOH(followed by acidification)then benzyl alcohol is produced.

(iii)When ethyl magnesium chloride is treated with methanol, an adduct is produced which gives propan-1-ol on hydrolysis.

(iv)When methyl magnesium bromide is treated with propane, an adduct is the product that gives 2- methylpropane-2-ol on hydrolysis.