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Chemistry Question on Catalysis

HOOC−(CH2)4−COOH+2C2H5OH−>[H2SO4][Toluene]C2H5OOC−CH2−COOCH5{HOOC - (CH_2)_4 - COOH + 2C_2H_5OH ->[H_2SO_4][Toluene] C_2H_5OOC -CH_2 - COOC H_5} The purpose of using toluene here is

A

to make both substances (acid & alcohol) miscible

B

that the product is insoluble in toluene

C

that the reactants are insoluble in water

D

because of the formation of low boiling azotrope

Answer

to make both substances (acid & alcohol) miscible

Explanation

Solution

Toluene is used in the reaction to make both substances (acid and alcohol) miscible.