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Question: HM between the roots of the equation \[{x^2} - 10x + 11 = 0\] is A. \[\dfrac{1}{5}\] B. \[\dfrac...

HM between the roots of the equation x210x+11=0{x^2} - 10x + 11 = 0 is
A. 15\dfrac{1}{5}
B. 521\dfrac{5}{{21}}
C. 2120\dfrac{{21}}{{20}}
D. 115\dfrac{{11}}{5}

Explanation

Solution

Here we are asked to find the harmonic mean of the roots of the given equation. The harmonic mean of the given values is nothing but the reciprocal of the arithmetic mean of the given values. First, we will find the roots of the given equation since the given equation is a quadratic equation it will have two roots. Then we will find the harmonic equation of those roots using the formula.

Formula Used: If α\alpha and β\beta are the roots then the quadratic equation can be written asx2(α+β)x+αβ=0{x^2} - (\alpha + \beta )x + \alpha \beta = 0.
The harmonic mean of aaand b$$$$ = \dfrac{{2(ab)}}{{a + b}}

Complete step-by-step solution:
The given quadratic equation is x210x+11=0{x^2} - 10x + 11 = 0 we aim to find the harmonic mean of this equation. For that, we need to first find the roots of this equation. We know that if α\alpha and β\beta are the roots then the quadratic equation can be written as x2(α+β)x+αβ=0{x^2} - (\alpha + \beta )x + \alpha \beta = 0 . On comparing the given equation with the general equation, we get the sum of the roots α+β=10\alpha + \beta = 10and the product of the rootαβ=11\alpha \beta = 11.
And we know that the formula for harmonic mean is 2(ab)a+b\dfrac{{2(ab)}}{{a + b}}, here we need to find the HM of the roots of the given equation that is α\alpha and β\beta .
Thus, HM of α\alpha and \beta $$$$ = \dfrac{{2(\alpha \beta )}}{{\alpha + \beta }}
We already know the values of αβ\alpha \beta andα+β\alpha + \beta . Substituting these in the formula we get
HM of α\alpha and β\beta =2(11)10 = \dfrac{{2(11)}}{{10}}
On simplifying the above, we get
HM of α\alpha and =115 = \dfrac{{11}}{5}
Thus, we have found the value of the harmonic mean of the roots of the given equation. Now let’s see the options to find the correct answer.
Option (a) 15\dfrac{1}{5} is an incorrect option as we got the HM as 115\dfrac{{11}}{5} in or calculation.
Option (b) 521\dfrac{5}{{21}} is an incorrect option as we got the HM as 115\dfrac{{11}}{5} in or calculation.
Option (c) 2120\dfrac{{21}}{{20}} is an incorrect option as we got the HM as 115\dfrac{{11}}{5} in or calculation.
Option (d) 115\dfrac{{11}}{5} is the correct option as we got the same value in our calculation.
Hence, option (d) 115\dfrac{{11}}{5} is the correct answer.

Note: We can also find the sum of roots and product of roots of a quadratic equation using the following method: If ax2+bx+c=0a{x^2} + bx + c = 0 is a quadratic equation then the sum of its roots =ba = \dfrac{{ - b}}{a} and product of its root =ca = \dfrac{c}{a}.