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Question

Chemistry Question on Redox reactions

Highest oxidation state of MnMn is present in

A

KMnO4 KMnO_4

B

K2MnO4K_2MnO_4

C

Mn2O3Mn_2O_3

D

MnO2MnO_2

Answer

KMnO4 KMnO_4

Explanation

Solution

Let the oxidation state of MnMn is xx. (a) KMnO4+1+x+(2)×4=0KMnO _{4}+1+x+(-2) \times 4=0 x7=0x-7 =0 x=+7x =+7 (b) K2MnO4(+1)×2+x+(2)×4=0K _{2} MnO _{4} (+1) \times 2+x+(-2) \times 4=0 x6=0x-6=0 x=+6x=+6 (c) Mn2O3x×2+(2)×3=0Mn _{2} O _{3} x \times 2+(-2) \times 3=0 2x=+62 x=+6 x=+3x=+3 (d) MnO2x+(2)×2=0MnO _{2} x+(-2) \times 2=0 x=+4x=+4 Thus, oxidation state of MnMn is highest in KMnO4KMnO _{4}.