Question

Highest oxidation state of manganese in fluoride is +4$(MnF_{4})$ but highest oxidation state in oxides is +7 $(Mn_{2}O_{7})$ because

• A. Fluorine is more electronegative than oxygen
• B. Fluorine does not posses d-orbitals
• C. Fluorine stabilizes lower oxidation state
• D. Both belong to the same group of the periodic table.

Answer 1

Answer: (D)

Both belong to the same group of the periodic table.

Answer 2

Oxygen can form $p\pi - p\pi$bonding while fluorine can form only single bonds.