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Question

Chemistry Question on p -Block Elements

HI can be prepared by all the following methods, except

A

\cePI3+H2O\ce{PI_3 + H_2 O}

B

\ceKI+H2SO4\ce{KI + H_2 SO_4}

C

\ceH2+I2>[pt]\ce{H_2 + I_2 ->[pt]}

D

\ceI2+H2S\ce{I_2 + H_2S}

Answer

\ceKI+H2SO4\ce{KI + H_2 SO_4}

Explanation

Solution

HI cannot be prepared by heating iodides with concentrated H2SO4 {H_2SO_4} because HI is a strong reducing agent and reduce H2SO4 {H_2SO_4} to SO2 {SO_2} and get themselves oxidised to I2 {I_2}. 2HI+H2SO4>SO2+I2+2H2O {2HI + H_2SO_4 -> SO_2 + I_2 + 2H_2 O}