Question

Hexafluorocobaltate (III) ion is a high spin complex. The hybrid state of cobalt is

• A. $d^2sp^3$
• B. $sp^3d^2$
• C. $dsp^2$
• D. $sp^3d.$

Answer 1

Answer: (B)

$sp^3d^2$

Answer 2

The formula of the ion is $[CoF_6]^{3^-}$. It is an octahedral complex with high spin. As such the hybrid stste sholuld be $sp^3d^2$