Question
Question: Here, \[{\text{EDT}}{{\text{A}}^{{\text{ - 4}}}}\] is a X dentate ligand. X is: A) mono B) Hexa ...
Here, EDTA - 4 is a X dentate ligand. X is:
A) mono
B) Hexa
C) tetra
D) Tertary
Solution
We have to know that in chemistry three types of chemical bond. There are ionic bonds, covalent bonds and coordinate bonds. Coordination chemistry is one of the major topics in chemistry. The coordination bond plays an important role in coordination chemistry. The complexes are formed in nature, the basis of coordination chemistry. In coordination chemistry, ligands are classified as mono dentate, di dentate, tri dentate etc,. This classification is based on the number of lone pairs of electrons donating atoms in ligands.
Complete answer:
We must have to know that the full form of EDTAis Ethylene Diamine Tetra Aceticacid.
The metal atom present in the complex is called the central metal atom. The atom which donate a lone pair of electrons to the central atom or the coordinate bond with the central atom is known as ligand.
X is the number of lone pairs donating atoms inEDTA - 4.
The number of lone pairs donating atoms in EDTA - 4 is 6.
Hence, X is hexa dentate ligand.
Option C is the correct answer.
Note:
We must remember that the oxidation state of the central metal atom is equal to the number of primary valencies. The coordination number of the central metal atom is equal to the secondary valency. In chemistry, substances are majorly divided into two types. This classification depends on the stability of the substance. Compound and complex are the classification of the substance in chemistry. In coordination chemistry, primary and secondary valency in the complex. The primary valency is ionic bonds. The primary valencies are non-directional. The secondary valencies are coordinate bonds. The secondary valence is directional. The structure of the complex depends on the secondary valence.