Question
Question: Here A, B and C are three points on a circle with center O such that \(\angle BOC = {30^ \circ }\) a...
Here A, B and C are three points on a circle with center O such that ∠BOC=30∘ and ∠AOB=60∘. If D is a point on the circle other than the arc ABC, find the value of ∠ADC.
(A) 90∘
(B) 40∘
(C) 45∘
(D) 110∘
Solution
In this question to find the value of the angle we use the theorem of the circle which states that an angle subtended by an arc of the circle at the center is double the angle is subtended at any point on the remaining circle of the same arc. Hence we find the value of the angle made at the center first and then we find the value of the angle made in the remaining part of the circle.
Complete step-by-step answer:
According to the question it is given that ∠AOB=60∘, ∠BOC=30∘
So, the value of ∠AOC, we get
∴∠AOC=∠AOB+∠BOC
Now we put the value of ∠AOB, ∠BOC in the above equation,
∴∠AOC=60∘+30∘
Hence we get the value of ∠AOC as
∴∠AOC=90∘
As we know that an angle which is subtended by an arc at the centre of the circle is double the angle subtended by that arc at any point on the remaining part of the circle.
According to the above statement we get the equation as
∴∠ADC=21∠AOC
Now we put the value of ∠AOC in the above equation, we get
∴∠ADC=21×90∘
By solving the above equation we get the value of ∠ADC as,
∴∠ADC=45∘
So, the value of the ∠ADC is 45∘.
So, the correct answer is “Option C”.
Note: In these type of questions first we detect which angle is formed at the center and which is made in the remaining part of the circle. And after this we should apply the theorem which made our calculation easy. And remember that if we find the value of the angle made at the center we double the value of the angle made in the remaining part. And if we are finding the value of the angle made in the remaining part of the circle we should half the value of the angle made at the center of the circle.