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Question: Henry’s law constant molality of methane in benzene at 298 K \(4.27 \times 10 ^ { 5 }\)mm Hg. The mo...

Henry’s law constant molality of methane in benzene at 298 K 4.27×1054.27 \times 10 ^ { 5 }mm Hg. The molefraction of methane in benzene at 298 under 760 mm Hg is

A

1.78×10−31.78 \times 10 ^ { - 3 }

B

17.4317.43

C

0.1140.114

D

2.8142.814

Answer

1.78×10−31.78 \times 10 ^ { - 3 }

Explanation

Solution

According to Henry’s law

x=pkH=7604.27×105=1.78×10−3\mathrm { x } = \frac { \mathrm { p } } { \mathrm { k } _ { \mathrm { H } } } = \frac { 760 } { 4.27 \times 10 ^ { 5 } } = 1.78 \times 10 ^ { - 3 }