Question
Question: Heats of combustion of \(C{{H}_{4}},{{C}_{2}}{{H}_{6}},\) and \({{C}_{2}}{{H}_{2}}\) is -212.8,-373....
Heats of combustion of CH4,C2H6, and C2H2 is -212.8,-373.0,-337.0 and -310.5 kcal respectively at the same temperature. The best fuel among these gases is:
A.CH4
B.C2H6
C.C2H4
D.C2H2
Solution
The meaning of best fuel means that the fuel should have a high calorific value. So, it is preferred to find the calorific value of the fuels by using the heat of combustion values and the molar mass.
Complete answer:
In order to answer this question, let us find out what calorific value is. A fuel is said to be a good fuel if it is economical and gives good energy. Efficiency of a fuel means the output the fuel gives, compared to the input energy we have to give to burn the fuel. A fuel which is highly efficient in nature is said to have a high calorific value. Calorific value is the amount of heat that is released by a fuel, on complete combustion, when a unit weight, rather than unit volume of it is used up. So, for a fuel to be a good fuel, it has to give the maximum amount of heat by using the minimum volume or minimum weight.
Now, we are given with 4 gases, whose heat of combustion is given. So we can find the calorific value by the formula:
Calorificvalue=molarmassHeatofcombustion
So, the calorific values of the respective gases are:
C.VCH4=16−212.8×103=−13.3×103C.VC2H6=30−373×103=−12.4×103C.VC2H4=28−337×103=−12.03×103C.VC2H2=26−310.5×103=11.92×103
From the given data, we find that the maximum calorific value is of methane C2H4.
Hence, it is the most efficient fuel and so our correct answer is option A.
Note:
It is to be noted that only the magnitude of the calorific value is needed to determine the efficiency of the fuel, sign is not important. Methane is used as a fuel in chemical processes carried out in industries and is transported as a refrigerated liquid(LMG).