Question
Question: Heating of \[MgC{l_2}.6{H_2}O\] gives anhydrous \[MgC{l_2}\] . If true enters 1, else enter 0....
Heating of MgCl2.6H2O gives anhydrous MgCl2 . If true enters 1, else enter 0.
Solution
MgCl2.6H2Oon heating will give MgCl2 and 6H2O and it means that MgCl2 is available in anhydrous form. MgCl2.6H2O removes water.
Complete step wise step answer:
MgCl2.6H2O undergoes partial hydrolysis on its own water molecules of crystallization when it is heated. MgCl2.6H2O upon heating gives MgCl2.2H2O and then Mg(OH)Cl or MgOCl + HCl which it is strongly heated gives MgO. When MgCl2 is strongly heated, then it forms MgO.
On heating, MgCl2.6H2O readily loses 4 molecules of water of crystallization to form MgCl2. Upon heating, MgCl2.6H2O went upon the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between 1500C and 500∘C. The remaining two molecules of water are not removed but react chemically with MgCl2 to form MgO. The thermal decomposition mechanisms and the intermediate morphology of MgCl2.6H2O and MgCl2.H2O were observed using integrated thermal analysis, X-ray diffraction, scanning electron microscope and chemical analysis.
This results showed that there was six steps in the thermal decomposition of MgCl2.6H2O: producing MgCl2.4H2O at 69∘C, MgCl2.2H2O at 129∘C, MgCl2.H2O (1⩽n⩽2) and Mg(OH)Cl at 167∘C ,
the conversion of MgCl2.H2O (1⩽n⩽2) to Mg(OH)Cl.3H2O by continuous dehydration and hydrolysis at 203∘C, the dehydration of Mg(OH)Cl.3H2O to Mg(OH)Cl at 235∘C , and hence the direct conversion of Mg(OH)Cl to the cylindrical particles of MgO at 415∘C.
So, It's true that MgCl2.6H2O on heating gives anhydrous MgCl2 ,
so we enter 1.
Note: MgCl2.6H2O went through the processes of dehydration and hydrolysis simultaneously accompanied by the release of HCl between 1500C and 500∘C. At a temperature higher than 500∘C, Mg(OH)Cl gradually releases part of HCl.