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Question

Chemistry Question on p -Block Elements

Heating an aqueous solution of aluminium chloride to dryness will give

A

\ceAl(OH)Cl2\ce{Al(OH) Cl_2}

B

\ceAl2O3\ce{Al_2O_3}

C

\ceAl2Cl6\ce{Al_2Cl_6}

D

\ceAlCl3\ce{AlCl_3}

Answer

\ceAl2O3\ce{Al_2O_3}

Explanation

Solution

The solution of aluminium chloride in water is acidic due to hydrolysis. AlCl3+3H2O>Al(OH)3+3HCl. {AlCl3 + 3H2O -> Al(OH)3 + 3HCl.} On heating it till dryness Al(OH)3 { Al(OH)3} is converted into Al2O3 {Al2O3} Al(OH)3>[Δ]Al2O3+3H2O {Al(OH)_3 ->[\Delta] Al_2O_3 + 3H_2 O }