Heating a mixture of ( {Cu\_2O}) and ( {Cu\_2S}) will give | Chemistry | SolveeIt

Question

Heating a mixture of ${Cu_2O}$ and ${Cu_2S}$ will give

$\ce{CuO + CuS}$

$\ce{Cu + SO_3}$

$\ce{Cu + SO_2}$

$\ce{Cu(OH)_2 + CuSO_4}$

Answer

$\ce{Cu + SO_2}$

Explanation

Solution

$2 Cu _{2} O + Cu _{2} S \longrightarrow 6 Cu + SO _{2}$
Cuprous sulphide brings about reduction of cuprous oxide. This reaction takes place in bessemer converter during metallurgy of copper.

Chemistry Question on Concentration of ores

Solution