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Question

Physics Question on Current electricity

Heater of an electric kettle is made of a wire of length LL and diameter d. It takes 44 minutes to raise the temperature of 0.5kg0.5\, kg water by 40K40\, K. This heater is replaced by a new heater having two wires of the same material, each of length LL and diameter 2d2 \,d. The way these wires are connected is given in the options. How much time in minutes will it take to raise the temperature of the same amount of water by 40K40\, K ?

A

4 if wires are in parallel

B

2 if wires are in series

C

1 if wires are in series

D

0.5 if wires are in parallel.

Answer

0.5 if wires are in parallel.

Explanation

Solution

H=V2R4=V2R/2H =\frac{ V ^{2}}{ R } 4=\frac{ V ^{2}}{ R / 2} t1=V2R/8t2 t _{1}=\frac{ V ^{2}}{ R / 8} t _{2} t1=2mint _{1}=2 \min t2=0.5mint _{2}=0.5 \min