Question

Heat required to convert one gram of ice at 0°C into steam at 100°C is (given L_steam = 536 cal/gm)

• A. 100 calorie
• B. 0.01 kilocalorie
• C. 716 calorie
• D. 1 kilocalorie

Answer 1

Answer: (C)

716 calorie

Answer 2

Conversion of ice (0°C) into steam (100°C) is as follows

Heat required in the given process $= Q_{1} + Q_{2} + Q_{3}$

$= 1 \times 80 + 1 \times 1 \times (100 - 0) + 1 \times 536 = 716cal$