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Question: Heat of hydrogenation of ethene is x<sub>1</sub> and that of benzene is x<sub>2</sub>. Hence resonan...

Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence resonance energy of benzene is-

A

x2 – 3x1

B

x1 + x2

C

3x1 – x2

D

x1 – 3x2

Answer

3x1 – x2

Explanation

Solution

+ 3H2 ¾® C6H12 (DrH)cal = 3x1

and (DrH)obs = x2

\ RE = (DrH)cal – (DrH)obs = 3x1 – x2