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Question: he value of Planck’s constant is 6.63 × 10–34Js. The velocity of light is 3 × 108 m/sec. Which value...

he value of Planck’s constant is 6.63 × 10–34Js. The velocity of light is 3 × 108 m/sec. Which value is closest to the wavelength of a quantum of light with frequency of 8 × 1015 sec–1 ?

A

5 × 10–18 m

B

4 × 10–8 m

C

3 × 107 m

D

2 × 10–25 m

Answer

4 × 10–8 m

Explanation

Solution

λ=cv=3×1088×1015=3.75×108λ=cv=3×1088×1015=3.75×108m\lambda = \frac{c}{v} = \frac{3 \times 10^{8}}{8 \times 10^{15}} = 3.75 \times 10 - 8\lambda = \frac{c}{v} = \frac{3 \times 10^{8}}{8 \times 10^{15}} = 3.75 \times 10^{8}m