Question
Question: he density of potassium bromide crystal is \[\,2.75g/c{m^3}\,\] and the length of an edge of the uni...
he density of potassium bromide crystal is 2.75g/cm3 and the length of an edge of the unit cell is 654pm .The unit cell of KBr is one of the three types of cubic unit cell. How many formula units of KBr are there in a unit cell? [KBr=119]
A.2
B.4
C.6
D.8
Solution
The answer for this question can be obtained by using the formula to calculate density of the unit cell. A unit cell's density is given as the ratio of the unit cell's mass and volume. The mass of a unit cell is proportional to the product of a unit cell's number of atoms and a unit cell's mass of each atom.
Formula used:
ρ=NA×a3Z×M
Where Z= Number of formula units
M= Molar mass of KBr
NA= Avogadro number
a = Edge length
Complete step by step answer:
Let us analyze the given data;
Density ρ=2.75g/cm3
Edge length a=654pm which is equal to 654×10−10cm
Molar mass of KBr =119g/mol
We Know that formula for calculating the density of unit cell is,
ρ=NA×a3Z×M
From this we can arrange the formula for calculating the number of formula units Z, that is,
Z=Mρ×NA×a3
=1192.75×6.022×1023×(654×10−10)3
=3.9 which is approximately equal to 4.
So, the right answer is option B that is 4.
Additional information:
Formula unit is the simplest ratio at which an ionic compound exists. Or simply we can say its empirical formula. The number of formula units is the number of atoms per unit cell which is denoted by Z.
Note:
Note that while doing the calculations 654pm should be changed to cm since the value of density in question is given in g/cm3, Otherwise the answer would be incorrect. 1centimetre is equal to 10000000000picometre . In addition, note that not all the particles in the shape of the unit cell are complete. Its corner particles will still add up to one whole particle for the fractional particles in the unit cell, its face particles (for face-centered lattices) add up to three whole particles, and one for the base particles.