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Chemistry Question on p -Block Elements

HClHCl behaves as......in the reaction: HCl+HF→H2+Cl+F−HCl+HF\xrightarrow{{}}H_{2}^{+}Cl+{{F}^{-}}

A

weak base

B

weak acid

C

strong base

D

strong acid

Answer

weak base

Explanation

Solution

In the reaction, HCl+HF→H2+Cl+F−HCl+HF\xrightarrow{{}}H_{2}^{+}Cl+{{F}^{-}} HClHCl is taking up a proton, hence it is acting as a base. Its conjugate acid (H2+Cl)(H_{2}^{+}Cl) has a strong tendency to loose proton, hence it is a strong acid, and therefore, its conjugate base (HC1) will be a weaker base.