HBr reacts with (CH\_{2} =CH-OCH\_{3}) under anhydrous condi... | Chemistry | SolveeIt

Question

HBr reacts with $CH_{2} =CH-OCH_{3}$ under anhydrous conditions at room temperature to give:

$CH_{3} CHO and CH_{3} Br$

$BrCH_{2} CHO and CH_{3}OH$

$BrCH_{2}- CH_{2}-OCH_{3}$

$H_{3}C-CHBr-OCH_{3}$

Answer

$H_{3}C-CHBr-OCH_{3}$

Explanation

Solution

First protonation occurs, two possible intermediates are (-1effect destabilizes carbocation) (+M effect stabilizes carbocation) II, is more favourable Hence, $Br^{\Theta}$ attacks, and product is

Chemistry Question on Chemical Reactions

Solution