HBr reacts with (CH\_2=CH??CH\_3) under anhydrous conditions... | Chemistry | SolveeIt

HBr reacts with $CH_2=CH??CH_3$ under anhydrous conditions at room temperature to give :

$CH_3CHO$ and $CH_3Br$

$BrCH_2CHO$ and $CH_3OHR$

$BrCH_2 ??CH_2 ??OCH_3$

$H_3C ??CHBr ??OCH_3$

Answer

$H_3C ??CHBr ??OCH_3$

Explanation

First protonation occurs, two possible intermediates are II, is more favourable Hence, $Br^?? attacks, and product is

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